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**oToom** · 08-14-2009, 11:43 AM

A challenge from over at freelancecode (.net).

Quote:Given the following information:

a = 26, b = 25, c = 24, d = 23 ..... x = 3, y = 2, z = 1

What is the sum of each letter of this sentence: "The quick brown fox jumped over the cow"? (Note, a white space has no value). Program this in any language you want.

Code:

/**

 * @(#)Sum_of_letters_in_a_sentence.java

 *

 * Sum_of_letters_in_a_sentence application

 *

 * @author 

 * @version 1.00 2009/8/14

 */

public class Sum_of_letters_in_a_sentence {

    public static void main(String[] args) {

        int A = 26, a = 26;

        int B = 25, b = 25;

        int C = 24, c = 24;

        int D = 23, d = 23;

        int E = 22, e = 22;

        int F = 21, f = 21;

        int G = 20, g = 20;

        int H = 19, h = 19;

        int I = 18, i = 18;

        int J = 17, j = 17;

        int K = 16, k = 16;

        int L = 15, l = 15;

        int M = 14, m = 14;

        int N = 13, n = 13;

        int O = 12, o = 12;

        int P = 11, p = 11;

        int Q = 10, q = 10;

        int R = 9, r = 9;

        int S = 8, s = 8;

        int T = 7, t = 7;

        int U = 6, u = 6;

        int V = 5, v = 5;

        int W = 4, w = 4;

        int X = 3, x = 3;

        int Y = 2, y = 2;

        int Z = 1, z = 1;

        System.out.println(T + h + e + q + u + i + c + k + b + r + o + w + n + f + o + x + j + u + m + p + e + d + o + v + e + r + t + h + e + c + o + w);

    }

}

G4143 · (This post was last modified: 08-14-2009 01:10 PM by G4143.)

I'll take a look at this Tonight or tomorrow. The solution will be in C...G4143

I think this will meet the requirements. I got a total of 450...G4143

Code:

#include <stdio.h>

#include <stdlib.h>

int mystrlen(char *s)

{

    int i = 0;

    while (*s++)

        ++i;

    return i;

}

char ch[] = "The quick brown fox jumped over the cow";

int main(int argc, char**argv)

{

    int i = 0, tot = 0;

    int len = mystrlen(ch);

    for (i = 0; i < len; ++i)

    {

        if (ch[i] > 64 && ch[i] < 91)

        {

            ch[i] = 91 - ch[i];

        }

        else if (ch[i] > 96 && ch[i] < 123)

        {

            ch[i] = 123 - ch[i];    

        }

        else 

        {

            ch[i] = 0;

        }

    }

    for (i= 0; i < len; ++i)

    {

        tot += ch[i];

    }

    fprintf(stdout, "total->%d\n", tot);

    exit(EXIT_SUCCESS);    

}

***Back_track*** · 08-14-2009, 05:44 PM

(08-14-2009 11:43 AM)Sketch Wrote: A challenge from over at freelancecode (.net).

Quote:Given the following information:

a = 26, b = 25, c = 24, d = 23 ..... x = 3, y = 2, z = 1

What is the sum of each letter of this sentence: "The quick brown fox jumped over the cow"? (Note, a white space has no value). Program this in any language you want.

Code:

/** * @(#)Sum_of_letters_in_a_sentence.java * * Sum_of_letters_in_a_sentence application * * @author * @version 1.00 2009/8/14 */ public class Sum_of_letters_in_a_sentence { public static void main(String[] args) { int A = 26, a = 26; int B = 25, b = 25; int C = 24, c = 24; int D = 23, d = 23; int E = 22, e = 22; int F = 21, f = 21; int G = 20, g = 20; int H = 19, h = 19; int I = 18, i = 18; int J = 17, j = 17; int K = 16, k = 16; int L = 15, l = 15; int M = 14, m = 14; int N = 13, n = 13; int O = 12, o = 12; int P = 11, p = 11; int Q = 10, q = 10; int R = 9, r = 9; int S = 8, s = 8; int T = 7, t = 7; int U = 6, u = 6; int V = 5, v = 5; int W = 4, w = 4; int X = 3, x = 3; int Y = 2, y = 2; int Z = 1, z = 1; System.out.println(T + h + e + q + u + i + c + k + b + r + o + w + n + f + o + x + j + u + m + p + e + d + o + v + e + r + t + h + e + c + o + w); } }

Ah that's exactly what i did in pascal basically lol
apparently this way isn't the best i like G4143's way the best

***drdebcol*** · (This post was last modified: 08-14-2009 06:00 PM by drdebcol.)

Interesting programming assignment ! Sketch did it in java using, i can say, bruteforce writing, because he wrote everything and summed it up !
G4143 did it in C++ using ASCII and return functions from it - i like it !
Now i want to add my solution in Pascal which is not like two past solutions,
i used set of checking and char loop ! Most of Pascal programmers don't know this exist :

Code:

program sum_of_letters;

uses wincrt;

var

 br,i:integer;

 s:string;

 function letter(a:char):integer;

 var

   i:char;

   br:integer;

 begin

   br:=0;

   if a in ['A'..'Z'] then

     begin

        for i:='A' to 'Z' do

          begin

             br:=br+1;

             if a=i then

               letter:=27-br;

          end;

     end

   else

     begin

     for i:='a' to 'z' do

          begin

             br:=br+1;

             if a=i then

             letter:=27-br;

          end;

     end;

   end;

begin

 s:='The quick brown fox jumped over the cow';

 br:=0;

 for i:=1 to length(s) do

   if not (copy(s,i,1)=' ') then

     br:=br+letter(s[i]); 

writeln(br); 

end.

And yeah, solution is 450 !

**oToom** · 08-14-2009, 10:20 PM

Yeah, the best way would be to use a loop, and assign each letter a value through the loop.
Then print out the sum of it all.

And yep, my answer was also 450 Wink

Keep it up guys!

FarOut · 09-23-2009, 11:06 AM

There's an easier way to do it. The sentence 'the quick brown fox jumps over the lazy dog' uses each letter of the alphabet once. Only once. Knowing that, you could've used a for() loop and just added the values from 1 to 26.

**oToom** · 09-23-2009, 06:41 PM

Thats well spotted there. I don't code Java now anymore. Into C#.
But thanks!

Alphablend · 12-09-2009, 08:14 AM

I think I'd probably do this one like oToom. Tongue

Now a challenge would be to make it for any entered sentence.
I will do it when I get the opportunity. Smile

codecaine · 12-09-2009, 08:28 AM

I did a java and c++ solution here. http://www.freelancecode.net/community/v...?f=13&t=11